F
(
λ
)
=
π
λ
2
(
1
−
e
−
λ
)
λ
2
+
4
π
2
\mathcal F(\lambda)=\frac{\pi\lambda^2\left(1-\mathrm e^{-\lambda}\right)}{\lambda^2+4\pi^2}
F
(
λ
)
=
λ
2
+
4
π
2
π
λ
2
(
1
−
e
−
λ
)
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Complex numbers
Quiz — Complex numbers
5 questions. Choose an answer: the correction appears at once, with an explanation.
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